90^@ Given, vec P vec Q=vec R So, we can write, vec R = sqrt(P^2Q^2 2PQ cos theta),where theta is the angle between the two vectors Or, R^2 =P^2 Q^2 2PQ cos theta Given, P^2 Q^2 = R^2 So, R^2 = R^2 2PQ cos theta Or, 2PQ cos theta =0Vector R = vector P vector Q if P = Q = R, find the angle between P and Q Let P=Q=R=AMagnitude of vectorR isR=(P^2Q^22PQcosthita)where thita is angle be Book a Trial With Our Experts The magnitude of two vectors p and q differ by 1 The magnitude of their resultant makes an angle of tan inverse (3 / 4) with p The angle between p and q is
09uel 3 If P Q Then Which Of The Following Is Not Correct P Q An The Following Is Not Correct P Are Unit Vectors And P Q Are
